Question for you lot here re: dialogs.
When opening a file open dialog box, is there a method to add a file filter to the input of the dialog function?
I want to do something like this:
Code:
var validTypes = [".mpeg",".mp4",".m4a",".mpg",".flv","*.mp3",".aac",".wav",".wma",".aif",".aiff",".au",".snd"];
fileName = openFileDialog(validTypes);
but it is unclear to me how a traditional filter works with the xwidget dialogs.
The standard way of doing it, if it was a Microsoft dialog box would be:
Code:
openFileDialog.filter= ".mpeg",".mp4",".m4a",".mpg",".flv","*.mp3",".aac",".wav",".wma",".aif",".aiff",".au",".snd";
but this does not seem to work.
Instead, I am using a filter function on the returned (output) value as follows:
Code:
var validTypes = ["mpeg","mp4","m4a","mpg","flv","mp3","aac","wav","wma","aif","aiff","au","snd"];
fileName = openFileDialog("");
if (validate_fileupload(fileName) === true ) {
PlayFile(fileName);
} else {
alert("incompatible file type");
}
function validate_fileupload(fileName)
{
var allowed_extensions = validTypes;
var file_extension = fileName.split('.').pop();
for(var i = 0; i < allowed_extensions.length; i++)
{
if(allowed_extensions[i]==file_extension)
{
return true; // valid file extension
}
}
return false;
}
This does the job but it is not the most elegant approach and so I ask: Is there a better method of adding an input filter to a file open dialog?
Documentation for xwidget is sparse as always and the inline documentation shows little as reference, so please help. It would be nice to know, then I could add it to a tutorial I am writing.
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